(√3/2)cosx-(1/2 )sinx=1/2
cos(x+π/6)=1/2
x=2{(nπ -(π /3)}2nπ
라고 저는 풀었는데 답은 x=nπ+π/3-(-1)^n (π /6)
라네요. 제가 풀이한것에서 틀린게 있나요? 설명좀부탁드려요
| 문제 레벨 | 고등수학(수능포함) |
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cos A = 1/2 일때 A 의 일반해에 맞게 하는 것이 좋을 것 같습니다.
수식이 정확하게 의미전달이 되지 않네요.
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좋은 자료 및 정보 부탁드립니다. ed hardy jeans for men
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두번째 식에서 cos 값이 1/2 가 나올려면 60, 120, 360+60, 360+120 등입니다.
세번째 식으로 60, 120, 360+60, 360+120 나오는 지 확인 요망